$A$ car starts from rest and rolls down a hill with constant acceleration. It travels a distance of $800 \ m$ in $10 \ s$. Find its acceleration. Also,find the force acting on it if its mass is $800 \ kg$.
(N/A) Given: Initial velocity $u = 0 \ m/s$,Distance $S = 800 \ m$,Time $t = 10 \ s$,Mass $m = 800 \ kg$.
Using the second equation of motion: $S = ut + \frac{1}{2}at^2$.
Substituting the values: $800 = (0 \times 10) + \frac{1}{2} \times a \times (10)^2$.
$800 = 0 + \frac{1}{2} \times a \times 100$.
$800 = 50a$.
$a = \frac{800}{50} = 16 \ m/s^2$.
Now,calculating the force using Newton's second law: $F = ma$.
$F = 800 \ kg \times 16 \ m/s^2 = 12800 \ N$.
Using the second equation of motion: $S = ut + \frac{1}{2}at^2$.
Substituting the values: $800 = (0 \times 10) + \frac{1}{2} \times a \times (10)^2$.
$800 = 0 + \frac{1}{2} \times a \times 100$.
$800 = 50a$.
$a = \frac{800}{50} = 16 \ m/s^2$.
Now,calculating the force using Newton's second law: $F = ma$.
$F = 800 \ kg \times 16 \ m/s^2 = 12800 \ N$.
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